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Download the climatology data file
o3mean.dat
(35 kB)
(per month are given: 17 latitudinal columns, each with 19 pressure rows)
pressure [hPa]: 1000 700 500 300 200 150 100 70 50 30 pressure [hPa]: 20 10 7 5 3 2 1 0.5 0.3
The 17 latitudinal bands are:
band: 1 2 3 4 5 6 7 8 9 latitude: -85 -75 -65 -55 -45 -35 -25 -15 -5 +5 band: 9 10 11 12 13 14 15 16 17 latitude: -5 +5 +15 +25 +35 +45 +55 +65 +75 +85 For latitude L [degrees] the band N is thus: N = nint{(L+90.)/10.} where nint is the function that rounds the number to an integer.Note that for latitudes below -85 or above +85 the climatology does not provide a value; use for these the value of bands 1 and 17, respectively.
d N [DU] / d P [mbar] = 0.78914 vmr [ppm]The integration per month and per latitudinal band is then simply a loop over the
nlevels=19
o3column=0. DO il=1,nlevels-1 dp=pressure(il)-pressure(il+1) o3column=o3column+dp*(o3mean(il)+o3mean(il+1))/2. ENDDO o3column=o3column*0.78914Download the total column data file
o3column.dat
(2 kB)
pressure [hPa]: 1000 700 500 300 200 150 100 70 50 30 altitude [km]: 0.0 3.0 5.5 9.5 12.0 14.0 16.5 19.0 21.0 24.5 pressure [hPa]: 20 10 7 5 3 2 1 0.5 0.3 altitude [km]: 27.0 32.0 34.5 37.0 41.0 44.0 49.5 55.0 59.0To do is more exact, the following do-loop would be needed:
altitude(1)=terrainheight DO il=2,nlevels ilm=il-1 altitude(il)=altitude(il) + # 1.e-3*(Rgas/g0)*temperature(ilm) * # ( log(pressure(ilm)) - log(pressure(il)) ) ENDDOwhere
nlevels=19
in this case and
terrainheight=0
[km] in general.
Furthermore:
temperature() is a temperature profile Rgas = 287.0, the gas constant for dry air [J/kg/K] g0 = 9.80665, the gravitational acceleration [m/s^2]